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• maxloo · 26 Jun 2026, 19:45 · official answer 1

  (a) Total number of seconds in one day	= $60 × 60 × 24$ = $86400$
  Amount of water leaked in one day	= $2.5 × 86400$
  	= $216000\ mℓ$
  	= $\boxed{216\ ℓ}$
  (b) Cost of leaked water in one day	= $\$0.15 × 216$ = $\boxed{\$32.40}$

  I understand this answer
• maxloo · 26 Jun 2026, 19:45 · official answer 2

  (a)

  Water leaked per minute	= $2.5 × 60$ = $150\ mℓ$
  Water leaked per hour	= $150 × 60$
  	= $9000\ mℓ$
  	= $9 ℓ$
  Water leaked per day	= $9 × 24$ = $\boxed{216\ ℓ}$

  (b)

  Cost of leaked water per day	= $0.15 × 216$
  	= $\boxed{\$32.40}$

  I understand this answer